# A body is projected from the ground with a speed u

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# A body is projected from the ground with a speed u

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>> A **body** **is** **projected** up **with** **a** **speed** **'u'** Question A **body** **is** **projected** up **with** **a** **speed** **'u'** and the time taken by it is T to reach the maximum height H. what will be the correct case. A it reaches 2H in 2T B It acquiers velocity Tu in 2T seconds C Same velocity at 2T D none Medium Solution Verified by Toppr Correct option is D). A body of** mass m** is projected from the ground with speed u at angle θ with horizontal. The power delivered by gravity to it at half of the maximum height from ground is: A 2mgu cosθ B 2mgu sinθ C 2mgu cos(90+θ) D Both (B) and (C) Medium Solution Verified by Toppr Correct option is B) H= maximum height = 2gu 2sin 2θ As we know p= dtdE or p= dtdU(y). . . . Jul 11, 2018 · **A body is projected from ground at angle** 60 **degree with the horizontal. If** it comes back to **ground** at distance 60(3)^1/2 meters from starting point then what is the time of flight? Physics.

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**A body is projected** with velocity **u** at an angle θ and reaches the **ground** at time T. What will be the time of flight if the **body is projected** with same **speed** at an angle (90°–θ)? Time of flight for angle of projection is given by,. A particle of mass m **is projected from the ground** with an initial **speed** `**u**_0` at an angle `alpha` with the horizontal. Click here👆to get an answer to your question ️ 010. 25. **A body** **is projected** **with a speed** **u** at an angle to the horizontal to have maximum range. At the highest point the velocity is : (A) zero (D) (B) **u** V2 (C) **u**. Click here👆to get an answer to your question ️ 010. 25. **A body** **is projected** **with a speed** **u** at an angle to the horizontal to have maximum range. At the highest point the velocity is : (A) zero (D) (B) **u** V2 (C) **u**. The cheetah's **body** is made for **speed** . The average cat only weighs 125 lbs. It has a small head, flattened rib cage and lean legs to minimize air resistance. When the cheetah bounds forward, it spends over half its time with all four paws off the **ground** . Nearby homes similar to 104 S Hayworth Ave #103 have recently sold between $680K to $1,620K at an average of $735 per.

# A body is projected from the ground with a speed u

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**A body** **is projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. mazda wreckers central coast. Q: A **body** is **projected** obliquely from the **ground** such that its horizontal range is maximum. If the change in its linear momentum, as it moves from half the maximum height to maximum height, is P, the change in its linear momentum as it travels from the point of projection to the landing point on the **ground** will be (a) P (b) √2 P (c) 2P (d) 2√2 P. mazda wreckers central coast. Q: A **body** is **projected** obliquely from the **ground** such that its horizontal range is maximum. If the change in its linear momentum, as it moves from half the maximum height to maximum height, is P, the change in its linear momentum as it travels from the point of projection to the landing point on the **ground** will be (a) P (b) √2 P (c) 2P (d) 2√2 P. Answer: Let the **body** be **projected** horizontally **with a speed** **u** from point A, at the top of a plane inclined at an angle \theta with the horizontal and let it strike the plane at point B , after time t, as shown in the figure.. The angular momentum of the **body**, about the point of projection, when it at highest point on its trajectory is 642926592 2.2 k+ 3.5 k+ 01:33. The acceleration along the **ground** is the same, so at 5000 feet down the runway, the **ground speed** is again 80 mph. b) Velocity is the change of displacement of **a body** with respect to time. Nov 16, 2017 · In this context, the energy delivered-to (downward motion) or drawn-from (upward motion) the** projectile** is the gravitational potential energy. Therefore, P = dU (y) dt If** ground** is made the zero reference potential, then the gravitational potential energy of a** projectile** of mass m at a height y from the** ground** is : U (y) = mgy..

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**A body is projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. As we know that a projectile motion is a combination to horizontal and verticle motion.The vetical component of intial velocity ‘**u**’ always remains constant ,i.e. in this case , **u** x= ucosQ, throughout the motion.So change in momentum in horizonal direction is 0 (zero). Now analysing the vertical direction motion we know intial velocity in ....

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# A body is projected from the ground with a speed u

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**A body** **is projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. **A** particle of mass m is **projected** **with** velocity v making an angle of 45° with the horizontal. When A ball is **projected** **from** **the** **ground** **with** **a** velocity **'u'** such that its range is maximum . then; A **body** **is** thrown vertically upward from a point **'A'** 125m above the **ground**. It goes up to a maximum A projectile is **projected** **with** kinetic. mazda wreckers central coast. Q: A **body** is **projected** obliquely from the **ground** such that its horizontal range is maximum. If the change in its linear momentum, as it moves from half the maximum height to maximum height, is P, the change in its linear momentum as it travels from the point of projection to the landing point on the **ground** will be (a) P (b) √2 P (c) 2P (d) 2√2 P. **A body** of mass m **is projected** from **ground** with **speed** **u** at an angle θ with horizontal. The power delivered by gravity when it is at half of maximum height from **ground** isA. mgucosθ/√2B. mgusinθ/√2C. mgusinθ/√2D. Both b and c. Oct 04, 2020 · Let us consider a ball **projected** at an angle θ with respect to horizontal x-axis with the initial velocity **u**. The point O is called the point of projection, θ is the angle of projection and OB = horizontal range. The total time taken by the particle from reaching O to B is called the time of flight. Now, (a).. A **body** is **projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. **A body is projected** with velocity **u** at an angle θ and reaches the **ground** at time T. What will be the time of flight if the **body is projected** with same **speed** at an angle (90°–θ)? Time of flight for angle of projection is given by,. A particle of mass m **is projected from the ground** with an initial **speed** `**u**_0` at an angle `alpha` with the horizontal. **A body is projected from the ground** with some **speed** at some angle with the horizontal. Taking the horizontal and vertical direction to be x and y axis respect. staccato c2 grip module; qualtrics pricing reddit; aita for being a stay at home parent and going back to school; cannot delete. A **body projected** vertically upward from the top of tower with **speed u** takes 9 s to reach the **ground**.Another **body projected** vertically downward with same **speed u** from the same point takes 4 s to reach the **ground**.Height of the tower is?Tags: Class 11 , Physics , Motion In A Plane Asked by azmat shaikh. A **body** is **projected** vertically up from **ground** with a **speed** √(gh). **A body** **projected** vertically with a velocity '**u**' from **ground**. Its velocity Welcome to Doubtnut. Doubtnut is World’s Biggest Platform for Video Solutions of Ph.... As we know that a projectile motion is a combination to horizontal and verticle motion.The vetical component of intial velocity ‘**u**’ always remains constant ,i.e. in this case , **u** x= ucosQ, throughout the motion.So change in momentum in horizonal direction is 0 (zero). Now analysing the vertical direction motion we know intial velocity in .... It burns from the opening ceremony until the end of the games. By vaccinating Fifi with a tiny, non-infectious piece of the viral protein, the scientists stimulated her immune system to make the special molecules. A body is projected from the ground with a speed 'u' at** an angle '0' with the horizontal.** When the body is at the highest point of the trajectory, its speed is 23 times its speed when it is at half the maximum height. The value of 'e' is 1) 30° 2) 45° 3) 60° 4) sin (23) Solution Verified by Toppr Solve any question of Motion in a Plane with:-. Click here👆to get an answer to your question ️ 010. 25. **A body** **is projected** **with a speed** **u** at an angle to the horizontal to have maximum range. At the highest point the velocity is : (A) zero (D) (B) **u** V2 (C) **u**. Jun 18, 2019 · **A body** **is thrown vertically upwards from ground with** a velocity **u**. It passes a point at a height h above the **ground** at time t1 while going up and at a time t2 while falling down. (t1 and t2 are measured from the instant of projecting **body** upwards). Then the relation between **u**, t1 and t2 and is:-(A) t1 + t2 = 2u/g (B) t2 - t1 = 2u/g (C) t1 + t2 .... A **body** of mass m is **projected** from **ground** with **speed u** at an angle θ with horizontal. ... Home > A **body** of mass m is **projected** from **ground** with **speed u** at an angle θ with horizontal. The power delivered by gravity when it is at half of maximum height from **ground** isA. mgucosθ/√2B. mgusinθ/√2C. mgusinθ/√2D. Both b and c. **A body**, rpojected horizontally **with a speed** . **u**. from the top of a tower of height . h, reaches the **ground** at a horizontally distance . R. from the tower. Another **body**, **projected** horizontally from the top of a tower of height . 4h, reaches the **ground** at horizontal distance . 2R. from the tower. The initial **speed** of the second **body** is. **A body** of mass m **is projected** from **ground** with **speed** **u** at an angle θ with horizontal. The power delivered by gravity when it is at half of maximum height from **ground** isA. mgucosθ/√2B. mgusinθ/√2C. mgusinθ/√2D. Both b and c. 2 days ago · Determine the actual **speed** and Air **speed** is the **speed** of an aircraft in relation to **ground speed** and wind **speed** are all vector visualise the problem as shown in Figure-1. 1. 90—-7B c) Find the resultant vector as a magnitude and bearing. Find the bearing of the plane. C. Find the bearing the pilot should fly, and find the plane's **ground speed**. **A body**, rpojected horizontally **with a speed** `**u**` from the top of a tower of height `h`, reaches the **ground** at a horizontally distance `R` from the towe. ... A particle **is projected** from **ground** with some initial velocity making an angle of `45^(@)` with the horizontal. It reaches a height of `7.5 m` above t. Jun 25, 2018 · Do you know, average .... Just as arteries divide up into smaller arteries and finally into thin -. Each bronchus divides into many smaller and smaller tubes until eventually ends up as a huge number of tiny air sacs, which comprise each lung. t = t1+t2 or t2 = t - t1. = 2 (**u**/g - t1) is the final answer. A **body** is **projected** upwards with a velocity **u**. May 13, 2020 · The Questions and Answers of **A body** **is projected** **with a speed** **u** m/s at an angle β with the horizontal. The kinetic energy at the highest point is 3/4th of the initial kinetic energy. The value of β is :a)30ºb)45ºc)60ºd)120ºCorrect answer is option 'A'.. Let a projectile be **projected** with **speed** **u** at angle θ from O and strike the **ground** at P with velocity v .The projectile will strike the **ground** at P after time equal to the time of the flight. Now, resolving the components of **u** in the horizontal and vertical direction, we have Horizontal and vertical component is given by, Therefore magnitude of velocity at **ground** is,. **A body is projected** with a velocity **u** with an angle of projectionθ. Change in velocity after the time (t) from the time of projection will be (1) gt (2)12gt2 (3) **u** sinθ (4) **u** cosθ Motion in A Plane Physics Practice questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, NCERT Exemplar Questions and PDF Questions with. **A** **body** **is** **projected** vertically upwards from the surface of the earth with a velocity equal to half A stone **projected** vertically up from the **ground** reaches a height y in its path at t1 seconds and A **body** **is** thrown vertically upwards with a velocity **u**. find the true statement from the following; A **body** **is** **projected** vertically up with a. **A body is projected** obliquely **from the ground** such that its horizontal range is maximum.If the change in its maximum height to maximum height, is `P`, the ch. model t upholstery; ff7 ever crisis news; kohler courage 20 oil capacity; psychedelic society; synology increase shared folder. . A **body** is **projected** upwards with a velocity \( **u** \). It passes through a certain point above the **ground** after \( t_{1} \). The time after which the **body** pass. Oct 04, 2020 · Let us consider a ball **projected** at an angle θ with respect to horizontal x-axis with the initial velocity **u**. The point O is called the point of projection, θ is the angle of projection and OB = horizontal range. The total time taken by the particle from reaching O to B is called the time of flight. Now, (a).. A **body**, **projected** horizuntally with a **speed** a from the top nfi, tower of herght \( h \), reaches the **ground** at a horizontal distance R from the tower. Anothe.

# A body is projected from the ground with a speed u

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# A body is projected from the ground with a speed u

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# A body is projected from the ground with a speed u

# A body is projected from the ground with a speed u

Mar 06, 2018 · 2.54m As we know that projectile motion follows **a **parabolic pathway,so we can discuss about **the **properties of parabola to find **the **radius of curvature of **the **projectile motion. Well **the **parabola **is **relatively flat on its two sides in comparison to its vertex.So we can consider sides of parabola to be part of very bigger circles that means,those parts have **a **greater radius of curvature. On .... 2 days ago · Determine the actual **speed** and Air **speed** is the **speed** of an aircraft in relation to **ground speed** and wind **speed** are all vector visualise the problem as shown in Figure-1. 1. 90—-7B c) Find the resultant vector as a magnitude and bearing. Find the bearing of the plane. C. Find the bearing the pilot should fly, and find the plane's **ground speed**. H = **u**^2/ (2g) when it crosses a height h its velocity has decreased to v and this must have been due to part of ki. Continue Reading. your **body** starts its journey with a kinetic energy. K.E. = (1/2) .mass. **u**^2 and. it reaches a maximum height H ,so it must have lost all its kinetic energy. A particle **is projected from the ground** with **speed u** at angle 60° from horizontal. asked Jan 12, 2020 in Physics by AmanYadav (55.9k points) jee main 2020 +1 vote. 1 answer. A small ball of mass m is thrown upward with velocity **u from the ground**. Horizontal Projectile: When **a body is projected** horizontally from a certain height ‘y’ vertically above the **ground** with initial velocity **u**. If friction is considered to be absent, then there is no other horizontal force that can affect the horizontal motion. The horizontal velocity, therefore, remains constant and so the object covers equal .... Click here👆to get an answer to your question ️ 010. 25. **A body** **is projected** **with a speed** **u** at an angle to the horizontal to have maximum range. At the highest point the velocity is : (A) zero (D) (B) **u** V2 (C) **u**. Jun 18, 2019 · **A body** **is thrown vertically upwards from ground with** a velocity **u**. It passes a point at a height h above the **ground** at time t1 while going up and at a time t2 while falling down. (t1 and t2 are measured from the instant of projecting **body** upwards). Then the relation between **u**, t1 and t2 and is:-(A) t1 + t2 = 2u/g (B) t2 - t1 = 2u/g (C) t1 + t2 .... **A body is projected from the ground** with some **speed** at some angle with the horizontal. Taking the horizontal and vertical direction to be x and y axis respect. staccato c2 grip module; qualtrics pricing reddit; aita for being a stay at home parent and going back to school; cannot delete. **A body is projected from the ground** with some **speed** at some angle with the horizontal. Taking the horizontal and vertical direction to be x and y axis respect. staccato c2 grip module; qualtrics pricing reddit; aita for being a stay at home parent and going back to school; cannot delete.

Includes: Aaton camera **body** #C533, **body** cap, 2 pcs 400` Aaton LTR 16mm magazines, 1pc battery 12 volts 1. at the same time, it has over 15 years production and exporting in 16mm 4 core cable. 295" In the 1970's, super 16mm was developed as a filming format primarily for productions which were to originate on 16mm (supported heavily by Aaton (tm) ,. **A body is projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. mazda wreckers central coast. Q: **A body is projected** obliquely **from the ground** such that its horizontal range is maximum. If the change in its linear momentum, as it moves from half the maximum height to maximum height, is P, the change in its linear momentum as it travels from the point of projection to the landing point on the **ground** will be (a) P (b) √2 P (c) 2P (d) 2√2 P. The angular momentum of the **body**, about the point of projection, when it at highest point on its trajectory is 642926592 2.2 k+ 3.5 k+ 01:33. The acceleration along the **ground** is the same, so at 5000 feet down the runway, the **ground speed** is again 80 mph. b) Velocity is the change of displacement of **a body** with respect to time. **A body** **is projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. The angular momentum of the **body**, about the point of projection, when it at highest point on its trajectory is 642926592 2.2 k+ 3.5 k+ 01:33. The acceleration along the **ground** is the same, so at 5000 feet down the runway, the **ground speed** is again 80 mph. b) Velocity is the change of displacement of **a body** with respect to time. A particle **is projected from the ground** with **speed u** at angle 60° from horizontal. asked Jan 12, 2020 in Physics by AmanYadav (55.9k points) jee main 2020 +1 vote. 1 answer. A small ball of mass m is thrown upward with velocity **u from the ground**.

**A body is projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. Includes: Aaton camera **body** #C533, **body** cap, 2 pcs 400` Aaton LTR 16mm magazines, 1pc battery 12 volts 1. at the same time, it has over 15 years production and exporting in 16mm 4 core cable. 295" In the 1970's, super 16mm was developed as a filming format primarily for productions which were to originate on 16mm (supported heavily by Aaton (tm) ,. Includes: Aaton camera **body** #C533, **body** cap, 2 pcs 400` Aaton LTR 16mm magazines, 1pc battery 12 volts 1. at the same time, it has over 15 years production and exporting in 16mm 4 core cable. 295" In the 1970's, super 16mm was developed as a filming format primarily for productions which were to originate on 16mm (supported heavily by Aaton (tm) ,.

A **body** is **projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is.(a) 40 ms-1 (b) ... both the stones will have the same **speed** when they hit the **ground**. (d) the **speed** cannot be determined with the given data Ans. (c) Related: Photosynthesis tests. A **body** is **projected** from the **ground** at an angle of 30° with the horizontal at an initial.

A boat, which has a **speed** of 5km/h in still water, crosses a river of width 1km along the shortest p... For an object **projected** **from the ground** with **speed** **u**, horizontal range is two times the maximum heig.... A particle **is projected from the ground** with **speed u** at angle 60° from horizontal. asked Jan 12, 2020 in Physics by AmanYadav (55.9k points) jee main 2020 +1 vote. 1 answer. A small ball of mass m is thrown upward with velocity **u from the ground**. A **body** of mass m is **projected** from **ground** with **speed u** at an angle θ with horizontal. ... Home > A **body** of mass m is **projected** from **ground** with **speed u** at an angle θ with horizontal. The power delivered by gravity when it is at half of maximum height from **ground** isA. mgucosθ/√2B. mgusinθ/√2C. mgusinθ/√2D. Both b and c. **A body** dropped from a height \[h\] with an initial **speed** zero, strikes the **ground** with a velocity\[3\,km/h\]. Another **body** of same mass is ... with an initial **speed** \[-{**u**}'=4km/h\] . Find the final velocity of second **body** with which it strikes the **ground** [CBSE PMT 1996]. louisiana webcam. **A body is projected** obliquely **from the ground** such that its horizontal range is maximum.If the change in its maximum height to maximum height, is `P`, the ch. model t upholstery; ff7 ever crisis news; kohler courage 20 oil capacity; psychedelic society; synology increase shared folder. Jun 25, 2018 · Do you know, average **speed** ? Yes, average **speed** = total distance/total time taken. Now, our first Target to find total distance and then total time taken during motion. Let's do it ! **body is projected** vertically upward with **speed** √gh, at heighest position **body** becomes rest. so, use formula, v² = u² + 2aS 0 = (√gh)² + 2(-g)S gh = 2gS⇒ S .... **A body** **is projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is. (a) 40 ms-1 (b) ... both the stones will have the same. A **body** is **projected** horizontally from the top of a tower with 30 ms-1. If g = 10ms-2 the velocity of that **body** after 4s is.(a) 40 ms-1 (b) ... both the stones will have the same **speed** when they hit the **ground**. (d) the **speed** cannot be determined with the given data Ans. (c) Related: Photosynthesis tests. A **body** is **projected** from the **ground** at an angle of 30° with the horizontal at an initial. The angular momentum of the **body**, about the point of projection, when it at highest point on its trajectory is 642926592 2.2 k+ 3.5 k+ 01:33. The acceleration along the **ground** is the same, so at 5000 feet down the runway, the **ground speed** is again 80 mph. b) Velocity is the change of displacement of a **body** with respect to time. Mar 06, 2018 · 2.54m As we know that projectile motion follows **a **parabolic pathway,so we can discuss about **the **properties of parabola to find **the **radius of curvature of **the **projectile motion. Well **the **parabola **is **relatively flat on its two sides in comparison to its vertex.So we can consider sides of parabola to be part of very bigger circles that means,those parts have **a **greater radius of curvature. On .... Feb 12, 2018 · **A body** **is projected** **with a speed** **u** at an angle to the horizontal to have maximum range at the highest point the velocity is?. Jun 25, 2018 · Do you know, average **speed** ? Yes, average **speed** = total distance/total time taken. Now, our first Target to find total distance and then total time taken during motion. Let's do it ! **body is projected** vertically upward with **speed** √gh, at heighest position **body** becomes rest. so, use formula, v² = u² + 2aS 0 = (√gh)² + 2(-g)S gh = 2gS⇒ S ....

# A body is projected from the ground with a speed u

# A body is projected from the ground with a speed u

Jul 05, 2019 · A particle of mass m **is projected** **with a speed** **u** **from the ground** at an angle θ = π/3 w.r.t. horizontal (x-axis). asked Jan 27, 2020 in Physics by Nakul01 ( 37.0k points) jee main 2020. In this context, the energy delivered-to (downward motion) or drawn-**from** (upward motion) the projectile is the gravitational potential energy. Therefore, P = dU (y) dt If **ground** **is** made the zero reference potential, then the gravitational potential energy of a projectile of mass m at a height y from the **ground** **is** : **U** (y) = mgy. Oct 04, 2020 · Let us consider a ball **projected** at an angle θ with respect to horizontal x-axis with the initial velocity **u**. The point O is called the point of projection, θ is the angle of projection and OB = horizontal range. The total time taken by the particle from reaching O to B is called the time of flight. Now, (a).. **A body is projected from the ground with a speed 'u**' at an angle '0' with the horizontal. When the **body** is at the highest point of the trajectory, its **speed** is 23 times its **speed** when it is at half the maximum height. The value of 'e' is 1) 30° 2) 45° 3) 60° 4) sin(23). **A body** is thrown horizontally from the top of a tower and strikes the **ground** after three seconds at an angle of 45∘ with the horizontal. Find the height of the tower and the **speed** with which the **body** was **projected**. take g =9.8 m / s 2A. 29.4 m / sB. 24.2 m / sC. 22.2 m / sD. 17 m / s. Includes: Aaton camera **body** #C533, **body** cap, 2 pcs 400` Aaton LTR 16mm magazines, 1pc battery 12 volts 1. at the same time, it has over 15 years production and exporting in 16mm 4 core cable. 295" In the 1970's, super 16mm was developed as a filming format primarily for productions which were to originate on 16mm (supported heavily by Aaton (tm) ,. 1 day ago · The United Kingdom of Great Britain and Northern Ireland, commonly known as the United Kingdom (UK) or Britain, is a sovereign country in Europe, off the north-western coast of the continental mainland. It comprises England,. **A body** **projected** vertically with a velocity '**u**' from **ground**. Its velocity Welcome to Doubtnut. Doubtnut is World’s Biggest Platform for Video Solutions of Ph.... When **a body** **is projected** with velocity **u** horizontally from a height h.Column IColumn IIaThe **speed** of **body** at any time t isp√2gh/u2 bIt will strike the **ground** after time t equal toq√2h/g cThe path followed by the **body** is expressed as y equal tor 1/2gx2/u2 dThe tangent of the angle θ made by velocity vector striking the **ground** with horizontal is equal tos√u2+g2t2. **A** **body** **is** **projected** up **with** **a** **speed** **'u'** and the time taken by it is T to reach the maximum height H . Pick out the correct statement A It reaches H/2 in T/2 sec B It acquires velocity U/2 in T/2 sec C Its velocity is U/2 at H/2 sec D Same velocity at 2T Solution The correct option is A It acquires velocity U/2 in T/2 sec.

body,projectedhorizuntally with aspeeda from the top nfi, tower of herght \( h \), reaches thegroundat a horizontal distance R from the tower. Anothe...bodyisprojectedfrom thegroundwith aspeed 'u' at an angle '0' with the horizontal. When thebodyis at the highest point of the trajectory, itsspeedis 23 times itsspeedwhen it is at half the maximum height. The value of 'e' is 1) 30° 2) 45° 3) 60° 4) sin(23)is projected from the groundwithspeed uat angle 60° from horizontal. asked Jan 12, 2020 in Physics by AmanYadav (55.9k points) jee main 2020 +1 vote. 1 answer. A small ball of mass m is thrown upward with velocityu from the ground.A body is projected obliquely from the groundsuch that its horizontal range is maximum.If the change in its maximum height to maximum height, is `P`, the ch...